Que:After covering a distance of 30 km with a uniform speed there is some defect in a train engine and therefore ,it's speed is reduced to 4/5of it's original speed .Consequently,the train reaches its destination late by 45 min . Had it happened after covering 18 km more, the train would have reached 9 min earlier . Find the speed of train and the distance of journey.
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Train proceeds at 4/5 S where S is his usual speed means 1/5 decrease in speed which
Now the main difference comes in those extra
18km and the change in difference of time = (45-36) min = 9 min.
Thus,
1/4*T = 9 min where T is the time required to cover the distance of 18 km.
T = 36 min = 36 /60 hours = 0.6 hours.
Speed of the Train = 18/0.6 = 30 kmph.
Distance =4/5×150=120KM
Now the main difference comes in those extra
18km and the change in difference of time = (45-36) min = 9 min.
Thus,
1/4*T = 9 min where T is the time required to cover the distance of 18 km.
T = 36 min = 36 /60 hours = 0.6 hours.
Speed of the Train = 18/0.6 = 30 kmph.
Distance =4/5×150=120KM
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130
here is your correct answer
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