Question

QUE:
Arrow 2.5 cm high is placed at 25 cm from a diverging mirror of a focal lenght 20 cm . find the nature , position & size of that mirror .
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Answer 1

Explanation:

H1 = +2.5cm

u = -25cm

f = +20cm

1/f = 1/v + 1/u

1/20 = 1/v -1/25

1/v = 1/20 + 1/25

1/v = 9/100

v = +11.11 cm

m = h2/h1 = -v/u

h2/2.5 = -11.11/-25

h2 = +1.11 cm

Hence the image will be formed at 11.11 cm behind the mirror, which will be virtual, erect and of 1.11cm size.

Answer 2

HEY MATE HERE IS YOUR ANSWER....

h1=+2.5

u=-25

f=+20

1/f= 1/v-1/u

1/v=1/f-1/u

=1/20+1/25

1/v=9/100

v=+11.11cm

m=h2/h1=-v/u

h2/2.5=-11.11/25

h2=+1.11

THEREFOR, THE IMAGE WILL BE FORMED AT 11.11 cm behind the mirror, which will be virtual,erect and of 1.11cm in size.

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