Question

que - calculate the mass of H20 produced when 6g of NAOH reacts with excess of HCL reaction-NAOH + HCL - NACL + H20​

Answer 1

The reaction between sadium chloride and the hydrochloric acid can be illustrated by,

NaOH + HCl --> NaCl + H2O

so here 1 mole of NaOH reacts with 1 mole of HCl. Hence it is required to convert the amount of HCl and NaOH in to moles.

Number of HCl moles

Concentration of the solution = 2.00M = 2 mol/ liter

Volume of the solution = 22.4 ml

Number of HCl moles = (2mol/1000 ml)*22.4 ml

= 0.0448 mol...

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