Question

Que:Draw the graph of the linear equation 3x + 4y = 6. At what points, the graph cuts X and Y-axis?

Answer 1

Answer:

Solution:

According to the question,

We get the equation,

3x + 4y = 6.

We need at least 2 points on the graph to draw the graph of this equation,

Thus, the points the graph cuts

(i) x-axis

Since, the point is on x axis, we have, y = 0.

Substituting y = 0 in the equation, 3x + 4y = 6,

We get,

3x + 4×0 = 6

⇒ 3x = 6

⇒ x = 2

Hence, the point at which the graph cuts x-axis = (2, 0).

(ii) y-axis

Since, the point is on y axis, we have, x = 0.

Substituting x = 0 in the equation, 3x + 4y = 6,

We get,

3×0 + 4y = 6

⇒ 4y = 6

⇒ y = 6/4

⇒ y = 3/2

⇒ y = 1.5

Hence, the point at which the graph cuts x-axis = (0, 1.5).

Plotting the points (0, 1.5) and (2, 0) on the graph.

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Hope it will be helpful :)

Answer 2

Answer:

In order to draw the graph of a line we need to know the intercept of the line.

The given equation of line is 3x + 4y = 6

So put x = 0

y = 3/2

Now put y = 0

x=2

So the two points are (0,3/2);(2,0)