Question

Que:.Find the energy of yellow photon in e.v wavelength for yellow light is 6000 A°

Answer 1

Given :

wavelength (lambda) = 6000 A

To Find :

Energy of Photon = ?

Concept/Formula :

Energy of Photon = hc/lambda

Calculation :

E = 6.626×10^-34×3×10^8 / 6000×10^-10

E = 3.313 × 10^-19 J

Answer :

Energy of Photon = 3.313 × 10^-19 J

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Answer 2

Answer:

The energy of one yellow photon in e.v wavelength for yellow light is 3.76 x 10^-19 J.

Explanation:

A photon of light with a wavelength in the visible spectrum of light between 570 and 590 nanometers is called a yellow photon.

The energy of a photon is calculated using the Planck-Einstein equation E = hc/λ, where h is Planck's constant (6.626 x 10^-34 J*s), c is the speed of light (2.998 x 10^8 m/s) and λ is the wavelength of the light. In the case of yellow light, λ = 6000 A°, so the energy of one yellow photon can be calculated as follows:

E = (6.626 x 10^-34 J*s) x (2.998 x 10^8 m/s)/(6 x 10^3 A°)

E = 3.76 x 10^-19 J

Therefore, the energy of one yellow photon in e.v wavelength for yellow light is 3.76 x 10^-19 J.

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