Question

Que. Find the minimum cross-sectional area of
wire, so that it doesnt break.
stress of
wire = 2x10*5 N/m² , starting
point
of
wire is
2 kg
and end point
wire
of is 4kg...​

Answer 1

Answer:

Correct option is

D

4 km

Let length =L

So, mass of length L=( Density of wire) (volume of wire)

Density of wire =ρ=5×10

3

Kg/m

3

Volume =LA(A= Area of cross section )

Stress=

Area

Force

2×10

8

=

A

mg

=

A

ρLAq

So, L=

ρ×g

2×10

8

=

5×10

3

×10

2×10

8

L=4000 m

L=4 km

option (d)