Que => Find the charge on 1 gram ions of Al^3+ .
● Don't spamming ●
Answers
Answered by
3
Your answer is --
we know that
1 gram ion = 1 mol ion
Now ,
1 mol Al^+3 ion = NA ion
Now, charge on 1 gram Al^+3 ion is
3 × NA e coulomb
where , e = elementary charge ( 1.6×10^-19)
NA = Avogadro number ( 6.023×10^23)
【 Hope it helps you 】
we know that
1 gram ion = 1 mol ion
Now ,
1 mol Al^+3 ion = NA ion
Now, charge on 1 gram Al^+3 ion is
3 × NA e coulomb
where , e = elementary charge ( 1.6×10^-19)
NA = Avogadro number ( 6.023×10^23)
【 Hope it helps you 】
Answered by
1
Hey Friend \(^_^)/
We know that,
1 gm atom = 1 mole of Atom
so, charge on 1 mole of electron = NA × Charge on 1 e-
= 6.023 × 10^23 × 1.6 × 10^-19 C.
= 9.6368 × 10^4
Thus charge on one mole of Al^3+ ion = 3×96398
= 289104 C.
We know that,
1 gm atom = 1 mole of Atom
so, charge on 1 mole of electron = NA × Charge on 1 e-
= 6.023 × 10^23 × 1.6 × 10^-19 C.
= 9.6368 × 10^4
Thus charge on one mole of Al^3+ ion = 3×96398
= 289104 C.
Similar questions