Math, asked by Anonymous, 11 months ago

Que=> Two Fraction are removed from the six fraction 1/3,1/6,1/9,1/12,1/15,1/18

So, that the sum of the remaining four fraction is 2/3 . The product of the two fraction removed is


(A) 1/180

(B)1/54

(C) 1/72

(D) 1/280


Give full explanation

Answers

Answered by Anonymous
56
Your answer is ----

The fraction have a common denominator 180, and their sum is

(60+30+20+15+12+10)/180

= 147/180

= (120+27)/180

= 2/3+1/12+1/15

The fraction removed are 1/12 and 1/15 , and

their product is 1/180.


So, option A is right


Anonymous: Cockroax...xD...bhai awesome
Anonymous: thanku behna
Answered by ans81
55
HEY MATE HERE IS YOUR ANSWER

This fraction have common denominator 180,
And their sum is

 \frac{(60 + 30 + 20 + 15 + 12 + 10}{180}
 =  \frac{120 + 27}{180}

 =  \frac{2}{3} +  \frac{1}{12}   +  \frac{1}{15}
Their product is
 \frac{1}{180}

So, the answer is
(option \: a)
Hope it will help you
be \: brainly
Similar questions