Question

*Que*- If an object starts from rest and accelerated with constant acceleration of 2 m/s^2. What is the velocity of that object after 20 second...?​

Answer 1

Explanation:

We know from Newtons equations of motion that

v=final velocity

u=initial velocity=0

a=acceleration=2m/s2

t=time=20s

v=u+at

v=0+2×20

v=40m/s

Answer 2

Given :

• Initial velocity of u = 0 m/s
• Acceleration=2m/s²

To Find :

Velocity of that object after 20 sec.

${\purple{\boxed{\large{\bold{Formula's}}}}}$

Kinematic equations for uniformly accelerated motion .

$\bf\:v=u+at$

$\bf\:s=ut+\frac{1}{2}at{}^{2}$

$\bf\:v{}^{2}=u{}^{2}+2as$

and $\bf\:s_{nth}=u+\frac{a}{2}(2n-1)$

Solution :

We have to find the velocity of that object after t=20 sec

By using equation of motion

$\sf\:v=u+at$

Now put the given values

$\sf\:v=0+2\times20$

$\sf\:v=0+40$

$\sf\:v=40ms^{-1}$

Hence ,The Velocity of that object after t = 20 sec

is 40 m/s .

${\purple{\boxed{\large{\bold{v=40ms^{-1}}}}}}$