Science, asked by komaldarda99, 2 months ago

que:. In a reaction, X+Y- Product, the rate of the reaction changes from 1 x 10^-3mol L^-1 s^-1 to 2 x 10^-3 mol L^-1 s^-1 is when the concentration of Y is doubled. The
rate of the reaction reaches 8 x 10^-3 mol L^-1 s^-1 when the concentration of both
X and Y are doubled. The rate law for the reaction can be written as,

Answers

Answered by abhaysharma10273
0

Answer:

For first order reaction,

A⟶B

Rate =k×[A]

Given, rate =2.0×10

−5

molL

−1

s

−1

[A] = Conc. of A = 0.01 M

So, 2.0×10

−5

=k×0.01

k=

0.01

2.0×10

−5

s

−1

=2.0×10

−3

s

−1

For first order reaction,

t

1/2

=

k

0.693

=

2.0×10

−3

0.693

=346.5=347s

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