Question

que is
factorise this ​

Answer 1

Answer:

= a² + 2ab + b² - c²

= (a+b)² - c²

{Since, (x+y)² = x² + 2xy + y²}

= (a+b+c) (a+b-c)

{Since, x² - y² = (x+y)(x-y) }

Hence the answer is : (a+b+c) (a+b-c)

Answer 2

Answer:

$\huge{\bf{\underline{\red{Answer :}}}}$

a² + 2ab + b2 - c²

=(a - b)² - c²

= [(a - b) - c )((a - b) +.c)]

= ( a - b - c) ( a - b + c )