Question

que no 2 (i)

plz help...

Answer 1

Please go through the attachment below for the answer.

Answer 2

HEY!! HERE IS UR ANS...
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ACCORDING TO THE QUESTION
.......FOR INFINITE SOLUTION........
$\frac{ {a}^{1} }{ {a}^{2} } = \frac{ {b}^{1} }{ {b}^{2} } = \frac{ {c}^{1} }{ {c}^{2} }$
$\frac{2}{ a- b} = \frac{3}{a +b } = \frac{ - 7}{ - (3a + b - 2)}$
=》2(a+b) = 3 (a-b) (CROSS MULTIPLIED)
=》2a + 2b = 3a + 3b
=》a = 5b -(i)
$\frac{3}{a + b} = \frac{7}{3a + b - 2}$
=》3 (3a + b -2) = 7(a+b)
=》9a + 3b - 6 = 7a + 7b
=》9(5b) + 3b -6 = 7(5b) + 7b [from eq (i)]
=》45b + 3b - 6 = 35b + 7b
=》48b - 6 = 42b
=》6b = 6
$b = \frac{6}{6}$
b = 1

put value of b in eq (i)
=》a = 5b
=》a= 5 (1)
=》a = 5

# RS
HOPE THIS HELPS....☺☺