que no 23 plsssss it's urgent
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Consider LHS (cosecA-sinA)(secA-cosA)(tanA+cotA)
= (1 ÷ sinA - sinA)(1÷cosA-cosA)(1÷cotA + cotA)
= (1-sin²A ÷ sinA)(1-cos²A÷cosA)(1+cot²A÷cotA)
= (cos²A÷sinA)(sin²A÷cosA)(cosec²A÷cotA)
= (cos²A÷sinA)(sin²A÷cosA)(1÷sin²A×(sinA÷cosA))
=1
RHS,
=(1÷tanA)×(1÷cotA)
=(1÷tanA)×tanA
=1
∴LHS=RHS
HENCE PROVED...
PLEASE MARK ME AS A BRAINLIEST!!
= (1 ÷ sinA - sinA)(1÷cosA-cosA)(1÷cotA + cotA)
= (1-sin²A ÷ sinA)(1-cos²A÷cosA)(1+cot²A÷cotA)
= (cos²A÷sinA)(sin²A÷cosA)(cosec²A÷cotA)
= (cos²A÷sinA)(sin²A÷cosA)(1÷sin²A×(sinA÷cosA))
=1
RHS,
=(1÷tanA)×(1÷cotA)
=(1÷tanA)×tanA
=1
∴LHS=RHS
HENCE PROVED...
PLEASE MARK ME AS A BRAINLIEST!!
bunny171:
you're brilliant!
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