Question

Que No 28
English
* 4.00
If the atomic masses of X and Y are 10 and 30
u respectively, then the mass of XY3 formed
when 120 g of Y2 reacts completely with X is
Reaction X + Y2 - XY: (unbalanced)
133.3 g​

Answer 1

Answer:

don't know sorry pls mark me as brain list

Answer 2

(There is some mistake in the given reaction. The correct unbalanced reaction is $\[X + {Y_2} \to X{Y_3}\]$.)

Given:

Atomic mass of X $=10$

Atomic mass of Y $=30$

Mass of $\[{Y_2}\]$ $=120 g$

To Find: Mass of $\[X{Y_3}\]$ when 120 g of $\[{Y_2}\]$ reacts completely with X

Solution:

The balanced chemical equation for the given reaction can be given as:

$\[2X + 3{Y_2} \to 2X{Y_3}\]$

Mass of X can be given as

$\[Mass = No.\,of\,moles \times molar\,mass\]$

Here, molar mass = atomic mass

Therefore,

Mass of X $\[ = 2 \times 10\]$

Mass of X $=20g$

Mass of $\[{Y_2}\]$ $\[ = 3 \times 60 = 180\,\,g\]$

180 g of $\[{Y_2}\]$ reacts with 20 g of X

1 g of $\[{Y_2}\]$ reacts with 20/180 g of X

120 g of $\[{Y_2}\]$ reacts with $\[\frac{{20}}{{180}} \times 120\,g = 13.33\,g\]$ of X

According to the law of conservation of mass,

Mass of $\[X{Y_3}\]$ = Mass of X + Mass of $\[{Y_2}\]$

Mass of $\[X{Y_3}\]$ $\[ = 13.33\,g + 120 = 133.33\,g\]$

Hence, the mass of $\[X{Y_3}\]$ when 120 g of $\[{Y_2}\]$ reacts completely with X is 133.33 g