Question

Que No. 5
1 marks
A question paper has two parts. A and B, each containing 10 questions. If a student has to choose 8 questions from part A and 5 questions from part 2
the number of ways that he can choose the questions is​

Answer 1

Answer:

Step-by-step explanation:

here 10 questions in part A out of which 8 question can be chosen as = 10C8

Similarly, 5 questions can be chosen from 10 questions of Part B as = 10C5

Hence, total number of ways,

=10C8×10C5=10!2!×8!×10!5!×5={10×92}×{10×9×8×7×65×4×3×2×1}=11340

Answer 2

Answer:

No. of questions in part A=10

No. of questions in part B=10

A student has to choose 8 from part A and 5 from part B

Required number of ways =( ¹⁰C8 ×¹⁰C5)=(¹⁰C2 × ¹⁰C2)=45×252=11340

Step-by-step explanation:

thanks my 10 ans