Math, asked by gaurmilan3, 4 months ago

Que
(xy-2y2) dx- (x2-3xy) dy=0​

Answers

Answered by aryanrewale10
0

Answer:

The given equation can be written as

dx

dy

=

3xy

(x

2

+y

2

)

.... (1)

Put y=vx⇒

dx

dy

=v+x

dx

dv

, equation (1) becomes

v+x

dx

dv

=−(

3xvx

x

2

+v

2

x

2

)=−(

3x

2

v

x

2

(1+v

2

)

)

∴v+x

dx

dv

=−(

3v

1+v

2

)

∴x

dx

dv

=

3v

−1−v

2

−v=

3v

−1−v

2

−3v

2

=

3v

−1−4v

2

8

3

1+4v

2

8v

dv=−∫

x

dx

Integrating we have

8

3

log(1+4v

2

)=−logx+logc.

⇒3log(1+4v

2

)+8logx=logc

⇒(1+4v

2

)

3

⋅x

8

=c

⇒(1+4

x

2

y

2

)

3

⋅x

8

=c

⇒(x

2

+4y

2

)

3

x

2

=c.

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