Question

Quebrenna
If the sum of nterm af an. A.P. whose first term is 5 and common difference is 36 is equal to the sum of 2n terms of another A. P . whose first term is 36 and common difference is 5. find n ​

Answer 1

Answer:

the value of n of this a.p. related question is 10

Answer 2

Step-by-step explanation:

1st AP

a = 5

d = 36

Sn = n/2 (2a + (n - 1)d)

= n/2 (36n - 26)

2nd AP

a = 36

d = 5

Sum of 2n terms = 2n/2 (2a + (2n-1)d)

= n (10n + 67)

Now it is given that these two AP are equal

n/2 (36n - 26) = n (10n + 67)

36n - 26 = 20n + 134

16 n = 160

n = 10

Hope it helps