Query the two cities in STATION with the shortest and longest CITY names, as well as their respective lengths (i.e.: number of characters in the name). If there is more than one smallest or largest city, choose the one that comes first when ordered alphabetically.
Answers
Answer:
Shortest is Van, longest is the real name of bangkok. Please mark me the brainliest.
To solve this problem, we can use the following SQL query:
SELECT CITY, LENGTH(CITY)
FROM STATION
WHERE LENGTH(CITY) = (SELECT MIN(LENGTH(CITY)) FROM STATION)
ORDER BY CITY
LIMIT 1;
The first query selects the city with the shortest name and its length. We first use the inner query to find the minimum length of the city names in the STATION table. We then select the cities with this minimum length using the WHERE clause, and order them alphabetically using the ORDER BY clause. Finally, we use the LIMIT clause to select only the first row, which will be the city that comes first alphabetically if there are multiple cities with the same shortest length.
SELECT CITY, LENGTH(CITY)
FROM STATION
WHERE LENGTH(CITY) = (SELECT MAX(LENGTH(CITY)) FROM STATION)
ORDER BY CITY
LIMIT 1;
The second query works similarly, except we use the MAX function to find the maximum length of the city names in the STATION table. We then select the cities with this maximum length using the WHERE clause, order them alphabetically using the ORDER BY clause, and use the LIMIT clause to select only the first row, which will be the city that comes first alphabetically if there are multiple cities with the same longest length.
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