Question

Ques 1: Calculate the molarity of a sulphuric acid solution in which the mole
fraction of water is 0.85.​

Answer 1

Explanation:

mol fraction of water in solution = 0.85

So mol of acid = 1-0.85 = 0.15

Now

m= nw×molecularwtofwater

1000×molofacid

m= 0.85×18

1000×0.15

=9.8mol/kg