Question

Ques 1.
Find the mean of first five whole Numbers.

Ques 2.
Find the Mode , Median and Mean of this Data.
38, 42, 35, 37, 45, 50, 32, 43, 43, 40, 36, 38, 43, 38, 47.

CBSE || Class 7th || Data Handling

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Answer 1

1st ans :- 0+1+2+3+4/5=10/5=2/1
2nd ans :- Mode = 38,43,
Median = There is no time to answer this
Mean = add them and divide with 15 and simplify it
Hope you got it
Plz mark me as a “Brainlist”

Answer 2

Given Question 1 :-

• Find the mean of first five whole Numbers.

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To Find :-

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• In Question 1 , We have to find the Mean of First Five Whole Numbers ! Here's the First Five whole numbers are 0, 1, 2, 3, 4 . Let's Find Out •

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Formula to be used:-

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$\sf {Mean} \: = \: {\sf \dfrac{Sum \: of \: All \: Observation}{No. \: of \: Observation}}$

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Solution with Step By Step Explanation:-

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First Five whole Numbers = $\sf{ 0, ~1, ~2,~ 3,~ 4.}$

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$\begin{gathered} \sf {Mean} \: = \: {\sf \dfrac{Sum \: of \: All \: Observation}{No. \: of \: Observation}} \\ \\ \\ =\sf \frac{0 \: + \: 1 + 2 + 3 + 4}{5} \\ \\ \\ = \sf \frac {\cancel{10^2}}{\cancel{5_1} } \\ \\ \\ = {\underline{\boxed{\sf{\pink{\: \: 2 \: \:}}}}}\end{gathered}$

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$\sf{Hence, The ~Mean~ of ~ First ~Five~ Whole~ Number ~is ~2}$

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Given Question 2:-

Find the Mode , Median and Mean of this Data.

38, 42, 35, 37, 45, 50, 32, 43, 43, 40, 36, 38, 43, 38, 47.

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To Find:-

Here, we Have to find the Mode and Median ! According to the Question, We have to find Mean too But we can't find because The Number of Values given can't Match the answer or In simply, The Question for mean is Wrong

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Formula To Be used:-

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•${\underline{\boxed{\frak{\pink{median}}}}}$ = $\sf{size \: of \: \bigg( \dfrac{ \: n + 1}{2}}\bigg)^{th \: item}$

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Solution With Step By Step Explanation:-

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Mode = Maximum no. of time occurring in Observation

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Here, The Number Which Is occurring Maximum Times in Observation Is Mode. If The Question have two values having same Maximum Times occurs In Observation Can be Mode.

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$\: \: \dag\: \: {\underline{\boxed{\frak{\orange{mode \: is \: 38 \: and \: 43\: both }}}}} \: \: \dag$

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Now, We have To Find the Median:-

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$\begin{gathered}\sf{\large{ = \: size \: of \: \bigg( \dfrac{ \: n + 1}{2}}}\bigg)^{th \: item} \\ \\ \\ \: \: \: = \sf{size \: of \: \bigg( \dfrac{ \: 15 + 1}{2}}\bigg)^{th \: item} \\\\ \\ = \large \sf\dfrac{\cancel{16}^8}{\cancel{2}_1} \\ \\ \\ = \large{\underline {\boxed{\frak{\green{ \: \: 8 \: \: }}}}} \end{gathered}$