Math, asked by student2961, 2 months ago

Ques 1) If x+y = 12 and xy=32, find the value of
х²+y²​

Answers

Answered by VεnusVεronίcα
37

We are given :

x + y = 12 . . . . . . (1)

xy = 32 . . . . . . . (2)

Let's square on both sides for (1) using (2) :

(x + y)² = + + 2xy = (12)²

+ + 2 (32) = 144

+ + 64 = 144

+ = 144 64

+ = 80

Know more :

(a b)² = + 2ab

(a + b) (a b) = -

(x + a) (x + b) = + (a + b)x + ab

(a + b)³ = + + 3 ab (a + b)

(a b)³ = 3 ab (a b)

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Therefore, the value of x² + y² is 80 when x + y = 12 and xy = 32.

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