Question

Ques. 1 (MMCO)
The position of a particle varies with time as ř = a sin 2tî + a cos 2tî + btê. Then the
A
trajectory of particle as seen by an observer moving with a velocity bê is a circle.
trajectory of the particle w.r.t. ground observer is a circle
B
C
angle between velocity and acceleration is 5
D
angle between velocity and acceleration is constant​

Answer 1

Step-by-step explanation:

Position of a particle x(t)=3t

3

−4t

2

+2 m

Differentiating w.r.t time we get v(t)=

dt

dx(t)

=9t

2

−8t m/s

Thus acceleration of the particle a(t)=

dt

dv(t)

=18t−8 m/s

2

⟹ a

∣

∣

∣

∣

∣

t=2s

=18×2−8=28 m/s

2