Ques.1
Two Coins are tossed once. Find The probability of getting:
(a) All Heads
(b) Atleast 2 Heads
(c) Atmost 1 Head
(d) Atmost 2 Tails
Answers
Step-by-step explanation:
Given :-
Two Coins are tossed once.
To find :-
Find The probability of getting:
(a) All Heads
(b) Atleast 2 Heads
(c) Atmost 1 Head
(d) Atmost 2 Tails
Solution :-
Given that
Two coins are tossed once.
We know that
If n coins are tossed once then the number of possible outcomes= 2^n
If two coins are tossed once then the total number of possible outcomes = 2² = 4
They are :
H H ,
H T
T H
T T
Head - H , Tail - T
a) Probability of getting all heads :-
Number of favourable outcomes to all heads = 1
Since HH
We know that
Probability of an event E = P(E)
Number of favourable outcomes/ Total number of all possible outcomes
Probability of getting all heads = 1/4
b) Probability of getting atleast 2 Heads :-
Number of favourable outcomes to atleast 2 heads = 1
We know that
Probability of an event E = P(E)
Number of favourable outcomes/ Total number of all possible outcomes
Probability of getting at least 2 heads = 1/4
c) Probability of getting at most 1 head :-
atmost 1 head means 0 heads and 1 head
H T , T H , T T ,
Number of favourable outcomes to all heads = 3
We know that
Probability of an event E = P(E)
Number of favourable outcomes/ Total number of all possible outcomes
Probability of getting at most 1 head = 3/4
d) Probability of getting at most 2 tails :-
at most 2 tails means 0 tails, 1 tails or 2 tails
H H , H T , T H , T T
Number of favourable outcomes to at most 1 tail = 4
We know that
Probability of an event E = P(E)
Number of favourable outcomes/ Total number of all possible outcomes
Probability of getting at most 1 tail = 4/4 = 1
Answer:-
a) Probability of getting all heads = 1/4
b)Probability of getting at least 2 heads = 1/4
c)Probability of getting at most 1 head = 3/4
d)Probability of getting at most 1 tail = 1
Used formulae:-
Probability of an event E = P(E)
Number of favourable outcomes/ Total number of all possible outcomes