Math, asked by mytwinklesujal, 1 month ago

Ques.1
Two Coins are tossed once. Find The probability of getting:
(a) All Heads
(b) Atleast 2 Heads
(c) Atmost 1 Head
(d) Atmost 2 Tails

Answers

Answered by tennetiraj86
1

Step-by-step explanation:

Given :-

Two Coins are tossed once.

To find :-

Find The probability of getting:

(a) All Heads

(b) Atleast 2 Heads

(c) Atmost 1 Head

(d) Atmost 2 Tails

Solution :-

Given that

Two coins are tossed once.

We know that

If n coins are tossed once then the number of possible outcomes= 2^n

If two coins are tossed once then the total number of possible outcomes = 2² = 4

They are :

H H ,

H T

T H

T T

Head - H , Tail - T

a) Probability of getting all heads :-

Number of favourable outcomes to all heads = 1

Since HH

We know that

Probability of an event E = P(E)

Number of favourable outcomes/ Total number of all possible outcomes

Probability of getting all heads = 1/4

b) Probability of getting atleast 2 Heads :-

Number of favourable outcomes to atleast 2 heads = 1

We know that

Probability of an event E = P(E)

Number of favourable outcomes/ Total number of all possible outcomes

Probability of getting at least 2 heads = 1/4

c) Probability of getting at most 1 head :-

atmost 1 head means 0 heads and 1 head

H T , T H , T T ,

Number of favourable outcomes to all heads = 3

We know that

Probability of an event E = P(E)

Number of favourable outcomes/ Total number of all possible outcomes

Probability of getting at most 1 head = 3/4

d) Probability of getting at most 2 tails :-

at most 2 tails means 0 tails, 1 tails or 2 tails

H H , H T , T H , T T

Number of favourable outcomes to at most 1 tail = 4

We know that

Probability of an event E = P(E)

Number of favourable outcomes/ Total number of all possible outcomes

Probability of getting at most 1 tail = 4/4 = 1

Answer:-

a) Probability of getting all heads = 1/4

b)Probability of getting at least 2 heads = 1/4

c)Probability of getting at most 1 head = 3/4

d)Probability of getting at most 1 tail = 1

Used formulae:-

Probability of an event E = P(E)

Number of favourable outcomes/ Total number of all possible outcomes

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