Ques 14 .pls ans ;ts my exam (ch-Rectilinear figure)
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This will be your figure.
Your answer will be governed by the mid - point theorem.
it states that a line joining the midpoints of two sides of a triangle will be parallel to the third side.
So if you take triangle ABC,
PQ joins the midpoints of AB and BC.
So PQ will be parallel to AC.
PQ || AC.
If you take triangle BDC,
similarly,
RQ || DB.
In a rhombus the diagonals are perpendicular to each other.
So, AC perpendicular to DB.
So, AC perpendicular to RQ (since DB || RQ)
Then, PQ perpendicular to RQ (since AC || PQ)
Hence proved.
Your answer will be governed by the mid - point theorem.
it states that a line joining the midpoints of two sides of a triangle will be parallel to the third side.
So if you take triangle ABC,
PQ joins the midpoints of AB and BC.
So PQ will be parallel to AC.
PQ || AC.
If you take triangle BDC,
similarly,
RQ || DB.
In a rhombus the diagonals are perpendicular to each other.
So, AC perpendicular to DB.
So, AC perpendicular to RQ (since DB || RQ)
Then, PQ perpendicular to RQ (since AC || PQ)
Hence proved.
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