Question

Ques 16:
If a = 16 and b = 5 then a+b2+ab/a3-b3 will
be ?
(A) 11
(B) 1/11
(C) 121
(D) Non
Ques 17:​

Answer 1

Answer:

$\frac{ {a}^{2} + {b}^{2} + ab }{ {a}^{3} - {b}^{3} } = \frac{ {a}^{2} + {b}^{2} + ab }{(a - b) ({a}^{2} + {b}^{2} + ab )} = \frac{1}{a - b} = \frac{1}{16 - 5} = \frac{1}{11}$

Answer 2

Step-by-step explanation:

this is correct........................