Question

Ques. 2 A car accelerates from rest at constant rate 'a' for some time after which it deaccelerates at
constant rate ß to come to rest. The max. velocity V reached if total time taken is t sec is
22.
(ə) v-Cen) (b) = (cm)ov-(din) cay v=C2)
aß
a+ß
(a) V=1
ab
(b) V=t
la-B)
( B2
=t
a+ß)
la-B​

Answer 1

Answer:

Explanation:

Rest =0

To rest =0

From 0 to 0