Question

ques 2 solve

..........
.




​

Answer 1

Explanation:

S

2−

+S→S

2

2−

K

1

=10

K

1

=

[S

2−

]

[S

2

2−

]

10=

[S

2−

]

[S

2

2−

]

..........(i)

S

2−

+2S→S

3

2−

K

1

′

=130

K

1

′

=

[S

2

2−

]

[S

3

2−

]

130=

[S

2−

]

[S

3

2−

]

..........(ii)

S

2

2−

+S→S

3

2−

................(iii) K

′′

K

′′

=K

1

′

/K

1

Dividing (ii) by (i), we get

K

′′

=

[S

2

2−

]

[S

3

2−

]

=

10

130

=13

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Answer 2

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