Question

ques 25 ii plz solve it

Answer 1

I hope you will be able to understand

Answer 2

$Given, \\ \\ \sec^{4}\theta - \tan^{4} \theta \\ \\ = (\sec^{2}\theta - \tan^{2}\theta)*(\sec^{2}\theta + \tan^{2}\theta) \\ \\ = 1* (\sec^{2}\theta + \tan^{2}\theta) \\ \\ = 1 + \tan^{2}\theta + \tan^{2}\theta \\ \\ = 1 + 2\tan^{2}\theta \\ \\ = R.H.S. \\ \\ \textbf{proved} \textit{ Identities used:-} 1. (a^{2} - b^{2}) = (a+b)(a-b) \\ \\ 2. \sec^{2}\theta - \tan^{2}theta = 1$