Question

ques 3 plzzzz urgent

Answer 1

We regard first M and m forming a single system.


Then,applying Newton’s second law,

we have

(M+m) a=F ……………(1)

Let F be applied on M.

From free body diagram of M

we have
following equation.
Ma=F-T………………….(2)

Therefore, T=F-Ma .

Substituting for a from Eq.(1),

we get,

T=F-M(F/M+m)=Fm/M+m…………(3).

This tension is the force on m.

Then, writing Eq. Of motion for m,

ma=T=Fm/(M+m).

But if we assume the force F applied on m then

the tension will be T=FM/(M+m).