Ques 7 class 9 ncert maths ex 13.1
Answers
Step-by-step explanation:
Let l, b and h be the length, breadth and height of the box.
Bigger Box:
l = 25cm
b = 20 cm
h = 5 cm
Total surface area of bigger box = 2(lb+lh+bh)
= [2(25×20+25×5+20×5)]
= [2(500+125+100)]
= 1450 cm2
Extra area required for overlapping 1450×5/100 cm2
= 72.5 cm2
While considering all over laps, total surface area of bigger box
= (1450+72.5) cm2 = 1522.5 cm2
Area of cardboard sheet required for 250 such bigger boxes
= (1522.5×250) cm2 = 380625 cm2
Smaller Box:
Similarly, total surface area of smaller box = [2(15×12+15×5+12×5)] cm2
= [2(180+75+60)] cm2
= (2×315) cm2
= 630 cm2
Therefore, extra area required for overlapping 630×5/100 cm2 = 31.5 cm2
Total surface area of 1 smaller box while considering all overlaps
= (630+31.5) cm2 = 661.5 cm2
Area of cardboard sheet required for 250 smaller boxes = (250×661.5) cm2 = 165375 cm2