Question

Ques: a bag contains 6 red balls and some green balls. if the probability of drawing a green ball is half that of a red ball then the number of green balls in the bag is

Answer 1

let the total balls be x
then,
P(getting a green ball)=1/2 [P(getting a red ball)]
no. of Green balls/x=1/2×6/x
no. of Green balls=1×6×x/2×x
no. of Green ballls=3

Answer 2

Answer:

The number of green balls in the bag=3 balls.

Step-by-step explanation:

Given that a bag contains 6 red balls and some green balls. If the probability of drawing a green ball is half that of a red ball.

we have to find the number of green balls.

Let number of green balls are x balls.

$\text{Probability of green balls=}\frac{\text{No. of green balls}}{\text{Total number of balls}}$

⇒ $P(\text{of green balls})=\frac{x}{6+x}$

$\text{Probability of red balls=}\frac{\text{No. of red balls}}{\text{Total number of balls}}$

⇒ $P(\text{of red balls})=\frac{6}{6+x}$

According to question, probability of drawing a green ball is half that of a red ball.

⇒ $\frac{x}{6+x}=\frac{1}{2}(\frac{6}{6+x})\\\\2x=6\\\\x=3$

Hence, the number of green balls in the bag=3 balls.