Question

Ques:
a body is projected in air such
that its hourizontal range is
equal to maximum height
Its angle of projection with
horizontal theta is such that??​

Answer 1

H=u²sin²Q/2g

R= u²sin2Q/g

R=H

u²sin²Q/2g=u²sinQcosQ×2/g

sinQ/2=cosQ

tanQ=4(it is not possible bcs the max value of tan is 1)

but the angle is 75.9