Ques. a boy has 4 different boxes and 5 different marbles. in how many ways can he place the marbles in the boxes such that each box has at least one marble ?
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put 2 box together and then keep the marble in then
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As when 4 marbles fit in 5 boxes with at least one in each box,
5! = 5* 4* 3* 2* 1= 120____I
4! = 4* 3* 2* 1= 24_____II
multiplying I and II,
120 * 24 = 2880.
dividing 2880 by each option given, only Op 2(240) and Op 4(36) divides exactly.
Now taking the product of 4 and 5 = 20.
dividing 240)and 36 by 20 gives a perfect remainder with 2.
Therefore, Ans =
--240.
5! = 5* 4* 3* 2* 1= 120____I
4! = 4* 3* 2* 1= 24_____II
multiplying I and II,
120 * 24 = 2880.
dividing 2880 by each option given, only Op 2(240) and Op 4(36) divides exactly.
Now taking the product of 4 and 5 = 20.
dividing 240)and 36 by 20 gives a perfect remainder with 2.
Therefore, Ans =
--240.
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