Physics, asked by Deepakpanwar2390, 11 months ago

Ques. A car is 250 metres behind the bus. The car and bus are moving with speed 60 km/hr and 35 km/hr respectively. The car will be ahead of bus by 250 metres in:

Answers

Answered by Krishya
0

Firstly, we need to find the relative speed

Relative speed = 60-35 = 25 Km/hr

For car to be ahead of bus by 250m,

Distance to be covered by car =250+250= 500m =0.5km

Therefore,

Time taken = 0.5/25=1/50 Hr or 3600/50 =72 seconds

Hope this helps! :)

Answered by Anonymous
1

QUESTION :-

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A car is 250 metres behind the bus. The car and bus are moving with speed 60 km/hr and 35 km/hr respectively. The car will be ahead of bus by 250 metres in:

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\huge{\boxed{\boxed {\mathfrak{\pink{A}\orange{N}\red{S}\green{W}\pink{E}\blue{R}}}}}

\\

\sf\red{First\:step\:is\:we\:need\:to\:find\:the\:relative\:speed}

\sf\pink{Relative\:speed} = \sf\orange{60\:-\:35\:=\:25\:km/h}

\\

\sf\purple{For\:car\:to\:be\:ahead\:of\:bus\:by\:250m,}

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\sf\green{Distance\:to\:be\:covered\:by\:car\:=}

\sf\green{250+250\:=\:500}

\implies \sf\blue{0.5km}

\\

\sf\pink{.°.Time\:taken\:=}\\\sf\orange{0.5/25\:= \:1/50\:hrs\:or\:72\:seconds}

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