Math, asked by shreygupta330, 5 hours ago

Ques) A shopkeeper always weighs 20% less than the
correct weight. One day, he weighed 20% more than
the quantity usually weighed by him. If the profit on
the correct weight is 20%, what is the effective
percentage of profit in this transaction?

Answers

Answered by biswadipmandal
0

Answer:

your Answer is here

Step-by-step explanation:

Let Sharad weight be ×

20%of × =48

20/100×x=48

×=48÷100/20

×=48× 20/100

×=240kg.

Hope It will help you!

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Answered by rajagrewal768
1

Concept:

Here the concept of percentage is used here.

So, to solve the problem of percentage we just need to divide the given number by hundred i.e. x%= x/100.

Given:

We know that shopkeeper always weighs 20% less than the correct weight.

Find:

We need to find the effective percentage of profit in this transaction.

Solutions:

Let we assume that correct weight be 100 kg and the cost price (C.P) be Rs. 100.

Then profit on the correct weight is 20% , therefore selling price (S.P.) = Rs. 120

As we know that he weighs 20% less than the original weight i.e.= 100*0.8= 80 kg

Now  one day he weight 20% more than 80 = 80*1.2= 96 kg

That means he sold 96 kg for Rs 120 and C.P of 96 kg is Rs 96.

Now, profit % = (120-96)/96 * 100 = 25%

Hence, the final answer is 25%.

#SPJ2

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