Question

Ques a: which teum
of an AP 2, 7, 12, 17 is 137​

Answer 1

Step-by-step explanation:

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this is the coding answer dont mind it

Answer 2

a = 2

d = 7-2

= 5

an = 137

an = a + (n-1)d

137 = 2 + (n-1)5

137 = 2 + 5n - 5

137 = -3 + 5n

137 + 3 = 5n

140 = 5n

n = 140/5

n = 28

Therefore, 137 is the 28th term of an AP.

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