Question

Ques & Calculate the magnitude of charge flowing through
a circuit if 3 uA of current flows through it
for 5 seconds​

Answer 1

Answer:

Total charge that flows in 2s is given by

q=It=5×2=10C

Now, charge on one electron is given by e=1.6×10

−19

C

N= number of electrons

q=Ne

⟹N=

e

q

⟹N=

1.6×10

−19

10

⟹N=6.25×10

19

Answer 2

Total charge that flows in 2s is given by

q=It=5×2=10C

Now, charge on one electron is given by e=1.6×10

−19

C

N= number of electrons

q=Ne

$⟹N= \frac{q}{e}$

$⟹N= \frac{10}{1.6 \times 10 {}^{ - 19} }$

$⟹N=6.25×10 {}^{19}$