Science, asked by rajpalkundu407, 11 months ago

Ques) by which initial velocity the ball will be thrown up ao that it can go up to a height of 40 m.
Ans) 28 m/s.

Answers

Answered by Anonymous

1

Explanation:

↙️↘️◆↙️↘️◆↙️↘️◆↙️↘️◆↙️↙️◆↘️↙️

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We know that VA2=U"2+2as

at maximum heightV=0anda=-gor-10 m/s

Hence height H=U*2/2¢g

H=40x40/2x10

H=80m.

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Answered by Anonymous

0

$\huge\tt\blue{Answer}$

We know that VA2=U"2+2as

at maximum heightV=0anda=-gor-10 m/s

Hence height H=U*2/2¢g

H=40x40/2x10

H=80m.

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