Social Sciences, asked by Anonymous, 9 months ago

Ques) Define points......??

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Answers

Answered by anushkasharma8840
4

Explanation:

  • A point in geometry is a location.
  • It has no size i.e. no width, no length and no depth.
  • A point is shown by a dot. A line is defined as a line of points that extends infinitely in two directions. ... Points that are on the same line are called collinear points
Answered by Anonymous
198

Explanation:

\huge\mathfrak\green{\bold{\underline{☘{ ℘ɧεŋσɱεŋศɭ}☘}}}

\red{\bold{\underline{\underline{❥Question᎓}}}}integrate the function:

 \frac{1}{ \sqrt{ {(2 - x)}^{2} + 1} }

\huge\tt\underline\blue{❯Answer❮</p><p> }

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Let 2-x=t

differentiating both sides w.r.t.x

0 - 1 =  \frac{dt}{dx}

dx =  - dt

Integrating the function w.r.t.x

∫ \frac{1}{ \sqrt{ {(2 - x)}^{2}  + t} } dx

Put the value of 2-x=t and dx=-dt

 =   ∫  \frac{ - dt}{ \sqrt{ {t}^{2}  + 1} }

 =  -   ∫  \frac{dt}{ \sqrt{ {t}^{2} +  {(1)}^{2}  } }

It is the form of :

  ∫  \frac{1}{ \sqrt{ {x}^{2}  +  {a}^{2} } } dx = log |x +  \sqrt{ {x}^{2}  +  {a}^{2} } | + c

∴ Replace a by 1 and x by t we get

 =  - log |t +   \sqrt{ {t}^{2} + 1 }  |  + c

 = log  { |t +  \sqrt{ {t}^{2}  + 1} | }^{ - 1}  + c

 = log \frac{1}{ |t +  \sqrt{ {t}^{2}  + 1} | } + c

 = log \frac{1}{ |2 - x +  \sqrt{ {(2 - x)}^{2} + 1 } | }  + c

 = log \frac{1}{ |2 - x +  \sqrt{4 +  {x}^{2}  - 4x + 1} | }  + c

 = log \frac{1}{ |2 - x +  \sqrt{ {x}^{2}  - 4x + 5} | }  + c

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