ques no 19...plzz ans it...
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since
a+b=11,
ab=24,
then
(a-b)²=(a+b)²-4ab,
(a-b)²=(11)²-4×24,
(a-b)²=121-96,
(a-b)²=25,
(a-b)=√25,
then
(a-b)=5
a+b=11,
ab=24,
then
(a-b)²=(a+b)²-4ab,
(a-b)²=(11)²-4×24,
(a-b)²=121-96,
(a-b)²=25,
(a-b)=√25,
then
(a-b)=5
Anonymous:
are u confirm that your ans is correct..
kk...
thanku...adee for answering
Answered by
1
a+b =11 and ab =24
a+b=-b/a =11/1
ab= c/a = 24/1
by using the standard form
ax2+bx2+c = 0
we get the values
a = 1, b = -11 , c = 24
a-b = 1-(-11)= 1+11= 12
hope this helps you❤️❤️
a+b=-b/a =11/1
ab= c/a = 24/1
by using the standard form
ax2+bx2+c = 0
we get the values
a = 1, b = -11 , c = 24
a-b = 1-(-11)= 1+11= 12
hope this helps you❤️❤️
no its kkk...
thanku for giving ans..
no matter it is correct or incorrect
kk
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