Ques no 2.
Find the value of sec^2 42degree - cosec^2 48degree.
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We know that,
sec theta = cosec ( 90 - theta)
=sec² 42 - cosec² 48
= (sec42 + cosec 48) ( sec 42 - cosec 48)
= (sec 42 + sec 42) (sec42 - sec42)
= (2 sec42) (0)
=0
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