Question

ques no. 46 plzzzzzzzzzz

Answer 1

/a/=10
/b/=2
a.b=12
/a//b/cos(theta)=12
10(2)cos(theta)=12
cos(theta)=3/5
sin(theta)=root of (1-(cos(theta))^2)
               =root of(1-(3/5)^2)
              =root  of ((4/5)^2)
   sin(theta) =4/5
axb=/a//b/sin(theta)
       =10(2)(4/5)
        =16
     answer is (b) option