ques no. 46 plzzzzzzzzzz
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/a/=10
/b/=2
a.b=12
/a//b/cos(theta)=12
10(2)cos(theta)=12
cos(theta)=3/5
sin(theta)=root of (1-(cos(theta))^2)
=root of(1-(3/5)^2)
=root of ((4/5)^2)
sin(theta) =4/5
axb=/a//b/sin(theta)
=10(2)(4/5)
=16
answer is (b) option
/b/=2
a.b=12
/a//b/cos(theta)=12
10(2)cos(theta)=12
cos(theta)=3/5
sin(theta)=root of (1-(cos(theta))^2)
=root of(1-(3/5)^2)
=root of ((4/5)^2)
sin(theta) =4/5
axb=/a//b/sin(theta)
=10(2)(4/5)
=16
answer is (b) option
gsnarayana:
its ok
plz mark as brainlist
okk
plz do that fast
process?? i m new
okk
tell me I'll do it
sorry it is not possible ,if only one answered the question
any way welcome
okk
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