Question

Ques: Solve the following equations and check the your result.
$\twoheadrightarrow \sf \: 3x = 2x + 18$
$\twoheadrightarrow \sf \: 5t - 3 = 3t - 5$
Note:
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Answer 1

Answer:

3x=2x+18

3x-2x=18

1x=18

therefore x=18

5t-3=3t-5

5t-3t=-5+3

2t=-2

t=1

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Answer 2

$\sf \red {Question - 1}$

$\twoheadrightarrow \sf \: 3x = 2x + 18$

$\sf \green {Answer}$

Given

3x = 2x + 18

Now,

Transporting 2x to LHS .

We obtain the equation as

$\sf 3x - 2x = 18 \\ \sf x = 18$

LHS = 3x = 3 × 18 = 54

RHS = 2x + 18 = 2 × 18 + 18 = 36 + 18 = 54

$\sf \: Hence , \red{LHS = RHS}$

$\sf \red {Question - 2}$

$\twoheadrightarrow \sf \: 5t - 3 = 3t - 5$

$\sf \green {Answer}$

We have

5t - 3 = 3t - 5

Transposing 3t to the LHS and -3 to the RHS,

Now,

We will get:

5t - 3t = -5 + 3

or

2t = -2

Dividing both sides by 2 :

t = -1

Let us Check :-

Put t = -1 in the LHS we have,

5t - 3 = 5(-1) - 3 = -5 -3 = -8

Similarly put t = -1 in the RHS:

3t - 5 = 3(-1) - 5 = -3 - 5 = -8

$\sf \: Hence , \red{LHS = RHS}$