Question

Ques: tan47°/cot43°=???​

Answer 1

Answer:

Step-by-step explanation:

Tan47/cot43= 1

LHS.

Tan47/cot43

Tan47/cot(90-47)

Tan47/Tan47 (Cot(90-∅) = Tan∅)

1. Ans

Answer 2

Answer:

Value is 1.

Step-by-step explanation:

L.H.S=

$\frac{ \tan(47 {}^{0} ) }{ \cot(43 {}^{0} ) } \\ = \frac{ \tan(47 {}^{0} ) }{ \cot(90 {}^{0} -47 {}^{0} ) } \\ = \frac{ \tan(47 {}^{0} ) }{ \tan(47 {}^{0} ) } ( \cot(90 - x) = \tan(x) ) \\ = 1 = rhs$

Hope you will understand✌️