Math, asked by KudalPratibha, 5 months ago

Ques. Using (x+a)(x+b)=x²+(a+b)x+ab.
1. 103x98
2. 103x104

Solve this question If you will then I will make you brainliest...​

Answers

Answered by bhavikachopra50
0

Hello !!

Here is your answer (with explanation) ↓

Here we use (x+a)(x+b)=x²+(a+b)x+ab.

1. 103*98

=(100+3)*{(100+(-2)}

Here, x=100 a=3 and b=-2

So, 100*100+ {(3+(-2)}100+3*-2

=10000+100-6

=10094

2. 103*104

=(100+3)*(100+4)

Here, x=100 a=3 and b=4

So, 100*100+(3+4)100+3*4

=10000+700+12

=10712

Hence, The answer becomes 10094 and 10712

Hope this helps you

Please mark as brainliest answer and follow me

Answered by Anonymous
0

Hello !!

Here is your answer (with explanation) ↓

Here we use (x+a)(x+b)=x²+(a+b)x+ab.

1. 103*98

=(100+3)*{(100+(-2)}

Here, x=100 a=3 and b=-2

So, 100*100+ {(3+(-2)}100+3*-2

=10000+100-6

=10094

2. 103*104

=(100+3)*(100+4)

Here, x=100 a=3 and b=4

So, 100*100+(3+4)100+3*4

=10000+700+12

=10712

Hence, The answer becomes 10094 and 10712

Hope this helps you

Please mark as brainliest answer and follow me

I thanked ur answers now u thank mine

Similar questions