Question

ques- What is the normality of a 96 per cent
solution of H2SO4 of specific gravity 1.847
HELP ME PLZZZ
I want explanation to this question and it's detailed method ​

Answer 1

Answer:

hi there is your answer

Mass of 1 litre of H2SO4 solution

=Vol.×Density

=1000×1.84=1840g

Mass of H2SO4 present in one litre 96% H2SO4 solution

=96100×1840=1766.4g

Strength of H2SO4 solution =1766.4g/L

(a) Normality =StrengthEq. mass=1766.449=36.05N

(b) Let the volume taken be V1 mL

Applying  N1V1=N2V2

N1=36.05N,V1=?,N2=N10,V2=1000 mL

36.05×V1×1000

So, V1=100036.05×10=2.77 mL

i.e., 2.77 mL of H2SO4 is diluted to one litre.

(c ) NBVBBefore dilution=NAVAAfter dilution  

10×36.05=VA×2

VA=180.25 mL

i.e., 10 mL of given H2SO4 is diluted to 180.25 mL.

Explanation:

hope it will help you..........

Answer 2

Answer:

36.05 N

Explanation:

Mass of 1 litre of H₂SO₄ Solution = Volume * Density

= 1000 * 1.84

= 1840 g

Mass of H₂SO₄ present in one litre 96% of H₂SO₄ Solution

= 96/100 * 1840

= 1766.4 g

Strength of H₂SO₄ Solution = 1766.4 g/L

Then,

Normality = 1766.4/49 = 36.05 N

Hope it helps!Brainliest it Bhai!