Question

ques11)
factorise 3a⁵-12a²b+12ab² into factors

whosoever will give correct answer will be marked as brainlist
and I will follow him or her too

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urgently needed​
need correct answer otherwise it will be reported​

Answer 1

Answer:

$3 {a}^{5 } - 12 {a}^{3} b + 12a {b}^{2} = 0$

$3 {a}^{5} - 6 {a}^{3} b \: - 6 {a}^{3} b \: + 12a {b}^{2} = 0$

take 3a^3 and -6ab common from this

$3 {a}^{3} ( {a}^{2} - 2b) \: - 6ab( {a}^{2} - 2b) = 0$

$(3 {a}^{3} - 6b) \: ( {a}^{2} - 2b) = 0$

$3 {a}^{3} - 6b = 0 \: and \: \: {a}^{2} - 2b = 0$

$3 {a}^{3} = 6b \: \: and \: \: {a}^{2} = 2b$

${a}^{2} = 2b \: \: and \: \: a = 2b$

$a = \sqrt{2b} \: and \: a = 2b$

Step-by-step explanation:

Hope this will help you