Question

Ques14: Verify whether the indicated numbers are zeros of the polynomials
corresponding to them in the following cases:
(i) f(x) = 3x + 1, x=-1/3
(ii) f(x) = x2-1, x = 1,-1​

Answer 1

Answer:

ANSWER

We know, if a is a zero of p(x), then p(a)=0.

Given, f(x)=x

2

−1.

Let x=1:

Then f(1)=(1)

2

−1=1−1=0.

That is, x=1 is a zero of the given polynomial f(x).

Now let x=−1:

Then f(−1)=(−1)

2

−1=1−1=0.

That is, x=−1 is a zero of the given polynomial f(x).

Hence, verified that x=1,−1 are the zeroes of the given polynomial.

Answer 2

MARK AS BRAINLIEST

Answer:

(i) f(x) = 3x + 1, x = −1/3

f(x) = 3x + 1

Substitute x = −1/3 in f(x)

f( −1/3) = 3(−1/3) + 1

= -1 + 1

= 0

Since, the result is 0, so x = −1/3 is the root of 3x + 1

(ii) f(x) = x2 – 1, x = 1,−1

f(x) = x2 – 1

Given that x = (1 , -1)

Substitute x = 1 in f(x)

f(1) = 12 – 1

= 1 – 1

= 0

Now, substitute x = (-1) in f(x)