Ques6.Alisha deposited an amount in bank which gives 10% simple interest. If she gets Rs.
45000 after 5 years, find the amount deposited by her?
Answers
Step-by-step explanation:
Given :-
Alisha deposited an amount in bank which gives 10% simple interest. She gets Rs.45000 after 5 years.
To find :-
The amount deposited by her.
Solution :-
Let the amount deposited by Alisha in a bank be Rs. X
Therefore, P = Rs. X
Rate of interest (R) = 10%
Time (T) = 5 years
Amount got by her after 5 years (A) = Rs. 45000
We know that
Simple Interest = PTR/100
=> S.I = (X×5×10)/100
=> S.I = 50X/100
=> S.I = X/2
Therefore, Simple Interest = Rs. X/2
We know that
Amount = Principal + Interest
=> 45000 = X+(X/2)
=> 45000 = (2X+X)/2
=> 45000 = 3X/2
=> 3X/2 = 45000
=> 3X = 45000×2
=> 3X = 90000
=> X = 90000/3
=> X = 30000
Therefore , Principal = Rs. 30000
(or)
We know that
Amount (A) = P[1+{(TR)/100}]
=> 45000 = X[1+{(5×10)/100}]
=> 45000 = X[1+(50/100)]
=> 45000 = X[1+(1/2)]
=> 45000 = X[(2+1)/2]
=> 45000 = X(3/2)
=> 45000×2/3 = X
=> X = 90000/3
=> X = 30000
Therefore , Principal = Rs. 30000
Answer :-
The deposited the amount in the bank by Alisha is Rs. 30000
Check :-
P = Rs. 30000
T = 5 years
R = 10%
Amount = P[1+{(TR/100)}]
=> A = 30000[1+{(5×10)/100}]
=> A = 30000[1+(50/100)]
=> A = 30000[ 1+(1/2)]
=> A = 30000[(3/2)
=> A = 90000/2
=> A = 45000
Therefore, Amount = Rs. 45000
Hence, Verified the given relations in the given problem.
Used Formulae:-
→ Simple Interest = PTR/100
→ Amount = P[1+{(TR/100)}]
- P = Principal
- T = Time
- R = Rate of Interest
Step-by-step explanation:
Step-by-step explanation:
Given :-
Alisha deposited an amount in bank which gives 10% simple interest. She gets Rs.45000 after 5 years.
To find :-
The amount deposited by her.
Solution :-
Let the amount deposited by Alisha in a bank be Rs. X
Therefore, P = Rs. X
Rate of interest (R) = 10%
Time (T) = 5 years
Amount got by her after 5 years (A) = Rs. 45000
We know that
Simple Interest = PTR/100
=> S.I = (X×5×10)/100
=> S.I = 50X/100
=> S.I = X/2
Therefore, Simple Interest = Rs. X/2
We know that
Amount = Principal + Interest
=> 45000 = X+(X/2)
=> 45000 = (2X+X)/2
=> 45000 = 3X/2
=> 3X/2 = 45000
=> 3X = 45000×2
=> 3X = 90000
=> X = 90000/3
=> X = 30000
Therefore , Principal = Rs. 30000
(or)
We know that
Amount (A) = P[1+{(TR)/100}]
=> 45000 = X[1+{(5×10)/100}]
=> 45000 = X[1+(50/100)]
=> 45000 = X[1+(1/2)]
=> 45000 = X[(2+1)/2]
=> 45000 = X(3/2)
=> 45000×2/3 = X
=> X = 90000/3
=> X = 30000
Therefore , Principal = Rs. 30000
Answer :-
The deposited the amount in the bank by Alisha is Rs. 30000
Check :-
P = Rs. 30000
T = 5 years
R = 10%
Amount = P[1+{(TR/100)}]
=> A = 30000[1+{(5×10)/100}]
=> A = 30000[1+(50/100)]
=> A = 30000[ 1+(1/2)]
=> A = 30000[(3/2)
=> A = 90000/2
=> A = 45000
Therefore, Amount = Rs. 45000