QUESTİON ABOUT BINOMIAL THEOREM
Find the coefficients of the expansion of (3a-b)^3(3a−b)^3. That is, represent (3a-b)^3(3a−b)^3 as
\alpha_0a^3+\alpha_1a^2b^1+\alpha_2a^1b^2+\alpha_3b^3
Try to compute these coefficients using the binomial theorem (instead of multiplying (3a-b)(3a−b) by itself two times).
Enter the values \alpha_0, \alpha_1, \alpha_2, \alpha_3α
0
Separate the values by commas, avoid spaces, do not include plus signs. For example, for the question (3a-b)^2(3a−b)^2
The answer would be: 9,-6,1
Answers
Answered by
5
Answer:
.....
Step-by-step explanation:
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Answered by
2
Answer:
27, -27, 9, -1
Step-by-step explanation:
From the question the answer would be: 9,-6,1
by the answer
(3a)^2 - 2.3a.b + b^2
= 3a^2 - 6ab +b^2
= 9.1 - 6.1.1 + 1 [(a=1, b=1)]
= 9 - 6 + 1
9, -6, 1
therefore (a=1, b=1)
Now,
(3a-b)^3 = 27a^3 - 3.9a^2.b + 3.3a.b^2 - b^3
= 27 - 27 + 9 - 1
27, -27, 9, -1
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