Math, asked by alkanakca34, 7 months ago

QUESTİON ABOUT BINOMIAL THEOREM
Find the coefficients of the expansion of (3a-b)^3(3a−b)^3. That is, represent (3a-b)^3(3a−b)^3 as

\alpha_0a^3+\alpha_1a^2b^1+\alpha_2a^1b^2+\alpha_3b^3


Try to compute these coefficients using the binomial theorem (instead of multiplying (3a-b)(3a−b) by itself two times).

Enter the values \alpha_0, \alpha_1, \alpha_2, \alpha_3α
0

Separate the values by commas, avoid spaces, do not include plus signs. For example, for the question (3a-b)^2(3a−b)^2
The answer would be: 9,-6,1

Answers

Answered by Anonymous
5

Answer:

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Step-by-step explanation:

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Answered by pronaykp
2

Answer:

27, -27, 9, -1

Step-by-step explanation:

From the question  (3a-b)^{2}  the answer would be: 9,-6,1

by the answer

(3a)^2 - 2.3a.b + b^2

= 3a^2 - 6ab +b^2

= 9.1 - 6.1.1 + 1    [(a=1, b=1)]

= 9 - 6 + 1

9, -6, 1

             

therefore (a=1, b=1)

Now,

(3a-b)^3 = 27a^3 - 3.9a^2.b + 3.3a.b^2 - b^3

= 27 - 27 + 9 - 1

27, -27, 9, -1

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